FS 05 /HOW MAKE IT: very shortly PICTORIAL GUIDE after GOMOKU ENGINE code | |||||
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game board summary flagx add ten flagx values M+ in line /001 M+ in line /002 M+ in line /003 M+ in line /004 LastMove /001 LastMove /002 predict low now predict high now 2d delay, dilay more delay now dilay +, delay + three: better end strategy FS05 summary |
Engine search sequences of signs in accordance with this rules: Sequence have five squares and of it three square is free (N). First (1) or last (3) free square on the same position in array "flagx" ("x_tack") must contains value 1000. Direction of value must be the same like a direction searching of sequence. At least one from next free squares must contains "flagx" value 100 in the different direction than direction of sequence. Here is all squares combinations. Engine rewrite values in "flagx" array from 1000 to 1098. One sample with found sequence of five squares. |
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examples in C++
write new "flagx" values in horizontal direction: //... //sud0 = plusx = pluso = middx = middo = liftx = lifto = 0; //for(loop = 0; loop < 5; loop++) { // write = column + loop; // switch(matRCboard[row][write]) { // case 'X': sumx += 1, xosum += 1; break; // case 'O': sumo += 1, xosum += 1; break; // case 'N': sud0++; // switch(x_tack[row][write]) { // case 0: break; // case 1: break; //C (100) (-) // case 10: if(sud0 == 2) middx++; plusx++; //M (1000) (-) // case 100: if(sud0 == 2) middx++; plusx++; //MM (2000) (-) // default: lagx += 1; //M,C (|,\,/) // if((x_tack[row][write] > 9) liftx++; //... // } //switch(x_tack) //... // } //switch(matRCboard) // } //for(loop) //... if((sumx == 2) && (sumx == xosum)) { for(loop = 0; loop < 5; loop++) { write = column + loop; if(matRCboard[row][write] == 'N') { switch(x_tack[row][write]) { case 10: if((middx == 0) && (plusx == 1) && (lagx > 0) && (lift == 0)) { if(flagx[row][write] < 1098) flagx[row][write] = 1098; } //... } //switch(x_tack) } //if(matRCboard) } //for(loop) } //if //... |
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